oracle查询重复数据和删除重复记录示例分享

一、查询某个字段重复

   select *
     from User u
     where u.user_name in (select u.user_name 
                 from User u
                group by u.user_name  having count(*) > 1)

二，删除表中某几个字段的重复

例：表中有条六条记录。   其中张三和王五   的记录有重复
TableA

id customer PhoneNo 
001 张三 777777 
002 李四 444444 
003 王五 555555 
004 张三 777777 
005 张三 777777 
006 王五 555555 
如何写一个sql语句将TableA变成如下 
001 张三 777777 
002 李四 444444 
003 王五 555555

测试环境

create table TableA ( id varchar(3),customer varchar(5),PhoneNo varchar(6)) 
insert into TableA select '001','张三','777777' 
union all select '002','李四','444444' 
union all select '003','王五','555555' 
union all select '004','张三','777777' 
union all select '005','张三','777777' 
union all select '006','王五','555555'

结果

delete TableA from TableA Twhere

exists( 
select 1fromtablea where customer=T.customer and phoneno=T.phoneno 
andid < tt.id
)

总结

该方法适用于有一个字段为自增性，例如本例中的：id

delete 表名 from 表名 as Twhere

exists( 
select 1from表名 where 字段A=T.字段A and 字段B=T.字段B,(....) 
and自增列 < T.自增列
)

三，查询并删除重复记录的SQL语句

查询及删除重复记录的SQL语句

1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断

select * from people 
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 

2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录

delete from people 
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

注:rowid为oracle自带不用该.....

3、查找表中多余的重复记录（多个字段）

select * from vitae a 
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) 

4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录

delete from vitae a 
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) 
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) 

5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录

select * from vitae a 
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) 
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) 

(二)
比方说
在A表中存在一个字段“name”，
而且不同记录之间的“name”值有可能会相同，
现在就是需要查询出在该表中的各记录之间，“name”值存在重复的项；

Select Name,Count(*) From A Group By Name Having Count(*) > 1 

如果还查性别也相同大则如下:

Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1 

(三)

方法一

declare @max integer,@id integer 
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >； 1 
open cur_rows 
fetch cur_rows into @id,@max 
while @@fetch_status=0 
begin 
select @max = @max -1 
set rowcount @max 
delete from 表名 where 主字段 = @id 
fetch cur_rows into @id,@max 
end 
close cur_rows 

set rowcount 0 方法二
＂重复记录＂有两个意义上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。
1、对于第一种重复，比较容易解决，使用
select distinct * from tableName
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录（重复记录保留1条），可以按以下方法删除

select distinct * into #Tmp from tableName 
drop table tableName 
select * into tableName from #Tmp 
drop table #Tmp 

发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。

2、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下
假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集

select identity(int,1,1) as autoID, * into #Tmp from tableName 
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID 
select * from #Tmp where autoID in(select autoID from #tmp2) 

最后一个select即得到了Name，Address不重复的结果集（但多了一个autoID字段，实际写时可以写在select子句中省去此列）

(四)
查询重复

select * from tablename where id in ( 
select id from tablename 
group by id 
having count(id) > 1 
)