sql通过日期判断年龄函数的示例代码

定义函数：

CREATE FUNCTION [dbo].[GetAge]  
(  
@BirthDay nvarchar(20) --生日  
)  
RETURNS varchar(20)  
AS  
BEGIN  
if(@BirthDay is NUlL or @BirthDay='')
return '';
 -- Declare the return variable here  
 DECLARE @age varchar(20)  
 DECLARE @years int  
 DECLARE @months int  
 DECLARE @days int  
 -- Add the T-SQL statements to compute the return value here  
 set @age = ''  
  
 set @years = year(GETDATE()) - year(@birthday)  
 set @months = month(GETDATE()) - month(@birthday)  
 if day(@birthday)<=day(GETDATE())  
   set @days = day(GETDATE()) - day(@birthday)  
 else  
   begin  
     set @months = @months - 1  
     if MONTH(@birthday) in (1,3,5,7,8,10,12)  
       set @days = 31-day(@birthday)+day(GETDATE())  
     else if MONTH(@birthday) in (4,6,9,11)  
       set @days = 30-day(@birthday)+day(GETDATE())  
     else if MONTH(@birthday) = 2  
       if (year(@birthday)%4 = 0 and year(@birthday)%100 <> 0) or year(@birthday)%400 = 0  
         set @days = 29-day(@birthday)+day(GETDATE())  
       else  
         set @days = 28-day(@birthday)+day(GETDATE())  
   end  
 if @months < 0  
   begin  
     set @years = @years - 1  
     set @months = @months + 12  
   end  
 if @years = 0 and @months = 0  
 begin  
     return convert(varchar,@days+1) + '天'  
  end  
 if @years > 0  
   set @age = cast(@years as varchar(5)) + '岁'  
 if @years < 3 and @months > 0 and @years>-1  
 begin  
   set @age = @age + cast(@months as varchar(5)) + '月'  
 end  
 if @years<0  
 set @age=''  
 RETURN @age  
END

使用函数：

到此这篇关于sql通过日期判断年龄函数的示例代码的文章就介绍到这了,更多相关sql日期计算年龄内容请搜索潘少俊衡以前的文章或继续浏览下面的相关文章希望大家以后多多支持潘少俊衡！